23 março 2019 - sábado 14:46 pm
Home Notícias Lixo dos rios Pinheiros e Tietê atinge cidades turísticas do interior de SP

Lixo dos rios Pinheiros e Tietê atinge cidades turísticas do interior de SP

0
31

‘):””},t.getDefinedParams=function(n,e){return e.filter((function(e){return n[e]})).reduce((function(e,t){return f(e,(function(e,t,n){t in e?Object.defineProperty(e,t,{value:n,enumerable:!0,configurable:!0,writable:!0}):e[t]=n;return e})({},t,n[t]))}),{})},t.isValidMediaTypes=function(e){var t=[“banner”,”native”,”video”];if(!Object.keys(e).every((function(e){return s()(t,e)})))return!1;if(e.video&&e.video.context)return s()([“instream”,”outstream”],e.video.context);return!0},t.getBidderRequest=function(e,t,n){return c()(e,(function(e){return 0

“));var s=f(g[r.size_id].split(“x”).map((function(e){return Number(e)})),2);a.width=s[0],a.height=s[1]}a.rubiconTargeting=(Array.isArray(r.targeting)?r.targeting:[]).reduce((function(e,r){return e[r.key]=r.values[0],e}),{rpfl_elemid:o.adUnitCode}),e.push(a)}else u.logError(“Rubicon bid adapter Error: bidRequest undefined at index position:”.concat(t),c,d);return e}),[]).sort((function(e,r){return(r.cpm||0)-(e.cpm||0)}))},getUserSyncs:function(e,r,t){if(!z&&e.iframeEnabled){var n=””;return t&&”string”==typeof t.consentString&&(“boolean”==typeof t.gdprApplies?n+=”?gdpr=”.concat(Number(t.gdprApplies),”&gdpr_consent=”).concat(t.consentString):n+=”?gdpr_consent=”.concat(t.consentString)),z=!0,{type:”iframe”,url:i+n}}},transformBidParams:function(e,r){return u.convertTypes({accountId:”number”,siteId:”number”,zoneId:”number”},e)}};function v(){return[window.screen.width,window.screen.height].join(“x”)}function m(e,r){var t=p.config.getConfig(“pageUrl”);return e.params.referrer?t=e.params.referrer:t||(t=r.refererInfo.referer),e.params.secure?t.replace(/^http:/i,”https:”):t}function b(e,r){var t=e.params;if(“video”===r){var n=[];return t.video&&t.video.playerWidth&&t.video.playerHeight?n=[t.video.playerWidth,t.video.playerHeight]:Array.isArray(u.deepAccess(e,”mediaTypes.video.playerSize”))&&1===e.mediaTypes.video.playerSize.length?n=e.mediaTypes.video.playerSize[0]:Array.isArray(e.sizes)&&0